(x+3)(x-3)-x^2=27

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Solution for (x+3)(x-3)-x^2=27 equation:


Simplifying
(x + 3)(x + -3) + -1x2 = 27

Reorder the terms:
(3 + x)(x + -3) + -1x2 = 27

Reorder the terms:
(3 + x)(-3 + x) + -1x2 = 27

Multiply (3 + x) * (-3 + x)
(3(-3 + x) + x(-3 + x)) + -1x2 = 27
((-3 * 3 + x * 3) + x(-3 + x)) + -1x2 = 27
((-9 + 3x) + x(-3 + x)) + -1x2 = 27
(-9 + 3x + (-3 * x + x * x)) + -1x2 = 27
(-9 + 3x + (-3x + x2)) + -1x2 = 27

Combine like terms: 3x + -3x = 0
(-9 + 0 + x2) + -1x2 = 27
(-9 + x2) + -1x2 = 27

Combine like terms: x2 + -1x2 = 0
-9 + 0 = 27
-9 = 27

Solving
-9 = 27

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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